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2144221213201 is a prime number
BaseRepresentation
bin11111001100111101100…
…010110011001000010001
321120222121110111120121221
4133030331202303020101
5240112331112310301
64321012554045041
7310625541406264
oct37147542631021
97528543446557
102144221213201
117573a4a7a981
122a7693419781
1312727881b752
1475ad0976cdb
153ab995bdda1
hex1f33d8b3211

2144221213201 has 2 divisors, whose sum is σ = 2144221213202. Its totient is φ = 2144221213200.

The previous prime is 2144221213181. The next prime is 2144221213207. The reversal of 2144221213201 is 1023121224412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2144057347600 + 163865601 = 1464260^2 + 12801^2 .

It is a cyclic number.

It is not a de Polignac number, because 2144221213201 - 215 = 2144221180433 is a prime.

It is a super-2 number, since 2×21442212132012 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2144221213207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072110606600 + 1072110606601.

It is an arithmetic number, because the mean of its divisors is an integer number (1072110606601).

Almost surely, 22144221213201 is an apocalyptic number.

It is an amenable number.

2144221213201 is a deficient number, since it is larger than the sum of its proper divisors (1).

2144221213201 is an equidigital number, since it uses as much as digits as its factorization.

2144221213201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 2144221213201 its reverse (1023121224412), we get a palindrome (3167342437613).

The spelling of 2144221213201 in words is "two trillion, one hundred forty-four billion, two hundred twenty-one million, two hundred thirteen thousand, two hundred one".