Base | Representation |
---|---|
bin | 1001110000000101000101… |
… | …00001000010011101001001 |
3 | 2210220221122201002220211021 |
4 | 10320002202201002131021 |
5 | 10302311140021431213 |
6 | 113334512133432441 |
7 | 4342135365534061 |
oct | 470024241023511 |
9 | 83827581086737 |
10 | 21443203311433 |
11 | 6918014278692 |
12 | 24a3a0549b721 |
13 | bc71157cacc7 |
14 | 541bdc6423a1 |
15 | 272bc0d31d8d |
hex | 1380a2842749 |
21443203311433 has 2 divisors, whose sum is σ = 21443203311434. Its totient is φ = 21443203311432.
The previous prime is 21443203311401. The next prime is 21443203311503. The reversal of 21443203311433 is 33411330234412.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11805456912649 + 9637746398784 = 3435907^2 + 3104472^2 .
It is a cyclic number.
It is not a de Polignac number, because 21443203311433 - 25 = 21443203311401 is a prime.
It is not a weakly prime, because it can be changed into another prime (21443203321433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10721601655716 + 10721601655717.
It is an arithmetic number, because the mean of its divisors is an integer number (10721601655717).
Almost surely, 221443203311433 is an apocalyptic number.
It is an amenable number.
21443203311433 is a deficient number, since it is larger than the sum of its proper divisors (1).
21443203311433 is an equidigital number, since it uses as much as digits as its factorization.
21443203311433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 21443203311433 its reverse (33411330234412), we get a palindrome (54854533545845).
The spelling of 21443203311433 in words is "twenty-one trillion, four hundred forty-three billion, two hundred three million, three hundred eleven thousand, four hundred thirty-three".
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