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214433142111302 = 2899371285678307
BaseRepresentation
bin110000110000011010011011…
…010000110111110001000110
31001010020121102100212002002112
4300300122123100313301012
5211101233033340030202
62040021120415141022
763111166106123402
oct6060323320676106
91033217370762075
10214433142111302
1162363648509064
12200726b5514772
139285c5cb96aba
143ad4895ada102
1519bcd71275b52
hexc3069b437c46

214433142111302 has 16 divisors (see below), whose sum is σ = 325610888284080. Its totient is φ = 105898750708608.

The previous prime is 214433142111233. The next prime is 214433142111311. The reversal of 214433142111302 is 203111241334412.

It is a super-3 number, since 3×2144331421113023 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 642672368 + ... + 643005939.

It is an arithmetic number, because the mean of its divisors is an integer number (20350680517755).

Almost surely, 2214433142111302 is an apocalyptic number.

214433142111302 is a deficient number, since it is larger than the sum of its proper divisors (111177746172778).

214433142111302 is a wasteful number, since it uses less digits than its factorization.

214433142111302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1285679335.

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 214433142111302 its reverse (203111241334412), we get a palindrome (417544383445714).

The spelling of 214433142111302 in words is "two hundred fourteen trillion, four hundred thirty-three billion, one hundred forty-two million, one hundred eleven thousand, three hundred two".

Divisors: 1 2 89 178 937 1874 83393 166786 1285678307 2571356614 114425369323 228850738646 1204680573659 2409361147318 107216571055651 214433142111302