Base | Representation |
---|---|
bin | 110000110000011010011110… |
… | …111110011111110001101111 |
3 | 1001010020121120201001211122222 |
4 | 300300122132332133301233 |
5 | 211101233200311401221 |
6 | 2040021130522225555 |
7 | 63111200463444635 |
oct | 6060323676376157 |
9 | 1033217521054588 |
10 | 214433204403311 |
11 | 6236367a694a63 |
12 | 200727123552bb |
13 | 9285c6ca6708a |
14 | 3ad48a00b3355 |
15 | 19bcd7697c9ab |
hex | c3069ef9fc6f |
214433204403311 has 2 divisors, whose sum is σ = 214433204403312. Its totient is φ = 214433204403310.
The previous prime is 214433204403277. The next prime is 214433204403331. The reversal of 214433204403311 is 113304402334412.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-214433204403311 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214433204403331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107216602201655 + 107216602201656.
It is an arithmetic number, because the mean of its divisors is an integer number (107216602201656).
Almost surely, 2214433204403311 is an apocalyptic number.
214433204403311 is a deficient number, since it is larger than the sum of its proper divisors (1).
214433204403311 is an equidigital number, since it uses as much as digits as its factorization.
214433204403311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 214433204403311 its reverse (113304402334412), we get a palindrome (327737606737723).
The spelling of 214433204403311 in words is "two hundred fourteen trillion, four hundred thirty-three billion, two hundred four million, four hundred three thousand, three hundred eleven".
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