Base | Representation |
---|---|
bin | 11111001101000101010… |
… | …011001010011010110101 |
3 | 21120222221112100022002111 |
4 | 133031011103022122311 |
5 | 240113112420111041 |
6 | 4321033523011021 |
7 | 310632011403403 |
oct | 37150523123265 |
9 | 7528845308074 |
10 | 2144351332021 |
11 | 757461473098 |
12 | 2a770ab09a71 |
13 | 127299779332 |
14 | 75b03d68473 |
15 | 3aba5c22981 |
hex | 1f3454ca6b5 |
2144351332021 has 2 divisors, whose sum is σ = 2144351332022. Its totient is φ = 2144351332020.
The previous prime is 2144351331989. The next prime is 2144351332061. The reversal of 2144351332021 is 1202331534412.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1358415891121 + 785935440900 = 1165511^2 + 886530^2 .
It is a cyclic number.
It is not a de Polignac number, because 2144351332021 - 25 = 2144351331989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2144351332061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072175666010 + 1072175666011.
It is an arithmetic number, because the mean of its divisors is an integer number (1072175666011).
Almost surely, 22144351332021 is an apocalyptic number.
It is an amenable number.
2144351332021 is a deficient number, since it is larger than the sum of its proper divisors (1).
2144351332021 is an equidigital number, since it uses as much as digits as its factorization.
2144351332021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 2144351332021 its reverse (1202331534412), we get a palindrome (3346682866433).
The spelling of 2144351332021 in words is "two trillion, one hundred forty-four billion, three hundred fifty-one million, three hundred thirty-two thousand, twenty-one".
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