Base | Representation |
---|---|
bin | 11111001101001110011… |
… | …011001100001000011111 |
3 | 21121000100012102112121001 |
4 | 133031032123030020133 |
5 | 240113421113244020 |
6 | 4321101032251131 |
7 | 310635550621453 |
oct | 37151633141037 |
9 | 7530305375531 |
10 | 2144504431135 |
11 | 75752a931790 |
12 | 2a7752240aa7 |
13 | 1272c23c1a21 |
14 | 75b1a41c663 |
15 | 3abb43b550a |
hex | 1f34e6cc21f |
2144504431135 has 32 divisors (see below), whose sum is σ = 2812569355584. Its totient is φ = 1556742144000.
The previous prime is 2144504431099. The next prime is 2144504431151. The reversal of 2144504431135 is 5311344054412.
It is a happy number.
It is not a de Polignac number, because 2144504431135 - 225 = 2144470876703 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2144504431094 and 2144504431103.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 156560607 + ... + 156574303.
It is an arithmetic number, because the mean of its divisors is an integer number (87892792362).
Almost surely, 22144504431135 is an apocalyptic number.
2144504431135 is a deficient number, since it is larger than the sum of its proper divisors (668064924449).
2144504431135 is a wasteful number, since it uses less digits than its factorization.
2144504431135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18795.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 2144504431135 its reverse (5311344054412), we get a palindrome (7455848485547).
The spelling of 2144504431135 in words is "two trillion, one hundred forty-four billion, five hundred four million, four hundred thirty-one thousand, one hundred thirty-five".
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