Base | Representation |
---|---|
bin | 11111001101101011000… |
… | …010001111001000111101 |
3 | 21121001120122121222001002 |
4 | 133031223002033020331 |
5 | 240120412003212432 |
6 | 4321220420300045 |
7 | 310653466550465 |
oct | 37155302171075 |
9 | 7531518558032 |
10 | 2144984429117 |
11 | 757756877332 |
12 | 2a7866b41625 |
13 | 12736a9927ba |
14 | 75b64088ba5 |
15 | 3abe15cbe62 |
hex | 1f36b08f23d |
2144984429117 has 2 divisors, whose sum is σ = 2144984429118. Its totient is φ = 2144984429116.
The previous prime is 2144984429047. The next prime is 2144984429153. The reversal of 2144984429117 is 7119244894412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1749109406521 + 395875022596 = 1322539^2 + 629186^2 .
It is a cyclic number.
It is not a de Polignac number, because 2144984429117 - 226 = 2144917320253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2144984429177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072492214558 + 1072492214559.
It is an arithmetic number, because the mean of its divisors is an integer number (1072492214559).
Almost surely, 22144984429117 is an apocalyptic number.
It is an amenable number.
2144984429117 is a deficient number, since it is larger than the sum of its proper divisors (1).
2144984429117 is an equidigital number, since it uses as much as digits as its factorization.
2144984429117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4644864, while the sum is 56.
The spelling of 2144984429117 in words is "two trillion, one hundred forty-four billion, nine hundred eighty-four million, four hundred twenty-nine thousand, one hundred seventeen".
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