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21450544142333 is a prime number
BaseRepresentation
bin1001110000010010110000…
…00100000101011111111101
32210221122121022011202201012
410320021120010011133331
510302421203300023313
6113342124405125005
74342515323551325
oct470113004053775
983848538152635
1021450544142333
116920140a54589
1224a53139b9765
13bc7a155c9827
145422d7560285
15272ea0522da8
hex1382581057fd

21450544142333 has 2 divisors, whose sum is σ = 21450544142334. Its totient is φ = 21450544142332.

The previous prime is 21450544142327. The next prime is 21450544142359. The reversal of 21450544142333 is 33324144505412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15963884403289 + 5486659739044 = 3995483^2 + 2342362^2 .

It is a cyclic number.

It is not a de Polignac number, because 21450544142333 - 222 = 21450539948029 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21450544142303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10725272071166 + 10725272071167.

It is an arithmetic number, because the mean of its divisors is an integer number (10725272071167).

Almost surely, 221450544142333 is an apocalyptic number.

It is an amenable number.

21450544142333 is a deficient number, since it is larger than the sum of its proper divisors (1).

21450544142333 is an equidigital number, since it uses as much as digits as its factorization.

21450544142333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 41.

Adding to 21450544142333 its reverse (33324144505412), we get a palindrome (54774688647745).

The spelling of 21450544142333 in words is "twenty-one trillion, four hundred fifty billion, five hundred forty-four million, one hundred forty-two thousand, three hundred thirty-three".