Base | Representation |
---|---|
bin | 10011111110100110… |
… | …000001111010110111 |
3 | 2001100222022110212222 |
4 | 103332212001322313 |
5 | 322413010021013 |
6 | 13504330432555 |
7 | 1356403425332 |
oct | 237646017267 |
9 | 61328273788 |
10 | 21451251383 |
11 | 9108743731 |
12 | 41a7b9275b |
13 | 203b25c273 |
14 | 1076d39619 |
15 | 858386508 |
hex | 4fe981eb7 |
21451251383 has 2 divisors, whose sum is σ = 21451251384. Its totient is φ = 21451251382.
The previous prime is 21451251361. The next prime is 21451251421. The reversal of 21451251383 is 38315215412.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21451251383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21451251583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10725625691 + 10725625692.
It is an arithmetic number, because the mean of its divisors is an integer number (10725625692).
Almost surely, 221451251383 is an apocalyptic number.
21451251383 is a deficient number, since it is larger than the sum of its proper divisors (1).
21451251383 is an equidigital number, since it uses as much as digits as its factorization.
21451251383 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 28800, while the sum is 35.
Adding to 21451251383 its reverse (38315215412), we get a palindrome (59766466795).
The spelling of 21451251383 in words is "twenty-one billion, four hundred fifty-one million, two hundred fifty-one thousand, three hundred eighty-three".
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