Base | Representation |
---|---|
bin | 11111001101110100100… |
… | …011000111110111110111 |
3 | 21121001222202222021221012 |
4 | 133031310203013313313 |
5 | 240121223333420142 |
6 | 4321244321342435 |
7 | 310660445350163 |
oct | 37156443076767 |
9 | 7531882867835 |
10 | 2145144045047 |
11 | 757828987123 |
12 | 2a78b0497a1b |
13 | 127394a7a4b3 |
14 | 75b7b357ca3 |
15 | 3ac0060a882 |
hex | 1f3748c7df7 |
2145144045047 has 2 divisors, whose sum is σ = 2145144045048. Its totient is φ = 2145144045046.
The previous prime is 2145144045043. The next prime is 2145144045061. The reversal of 2145144045047 is 7405404415412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2145144045047 - 22 = 2145144045043 is a prime.
It is a super-3 number, since 3×21451440450473 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2145144044995 and 2145144045013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2145144045041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072572022523 + 1072572022524.
It is an arithmetic number, because the mean of its divisors is an integer number (1072572022524).
Almost surely, 22145144045047 is an apocalyptic number.
2145144045047 is a deficient number, since it is larger than the sum of its proper divisors (1).
2145144045047 is an equidigital number, since it uses as much as digits as its factorization.
2145144045047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 358400, while the sum is 41.
The spelling of 2145144045047 in words is "two trillion, one hundred forty-five billion, one hundred forty-four million, forty-five thousand, forty-seven".
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