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21451442110481 is a prime number
BaseRepresentation
bin1001110000010100011011…
…00101100100000000010001
32210221201220212212021102202
410320022031211210000101
510302430023140013411
6113342353443452545
74342546506265265
oct470121545440021
983851825767382
1021451442110481
116920561919319
1224a5524687155
13bc7b29661426
1454238090c0a5
1527300429c83b
hex13828d964011

21451442110481 has 2 divisors, whose sum is σ = 21451442110482. Its totient is φ = 21451442110480.

The previous prime is 21451442110367. The next prime is 21451442110499. The reversal of 21451442110481 is 18401124415412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18254555326225 + 3196886784256 = 4272535^2 + 1787984^2 .

It is a cyclic number.

It is not a de Polignac number, because 21451442110481 - 214 = 21451442094097 is a prime.

It is a super-3 number, since 3×214514421104813 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (21451442112481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10725721055240 + 10725721055241.

It is an arithmetic number, because the mean of its divisors is an integer number (10725721055241).

Almost surely, 221451442110481 is an apocalyptic number.

It is an amenable number.

21451442110481 is a deficient number, since it is larger than the sum of its proper divisors (1).

21451442110481 is an equidigital number, since it uses as much as digits as its factorization.

21451442110481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40960, while the sum is 38.

Adding to 21451442110481 its reverse (18401124415412), we get a palindrome (39852566525893).

The spelling of 21451442110481 in words is "twenty-one trillion, four hundred fifty-one billion, four hundred forty-two million, one hundred ten thousand, four hundred eighty-one".