Base | Representation |
---|---|
bin | 11111001101111000101… |
… | …111001010101011101111 |
3 | 21121002011200012011220111 |
4 | 133031320233022223233 |
5 | 240121344330424101 |
6 | 4321255311400451 |
7 | 310662260532502 |
oct | 37157057125357 |
9 | 7532150164814 |
10 | 2145214311151 |
11 | 75786460a08a |
12 | 2a790bb23127 |
13 | 1273a64b0182 |
14 | 75b86809139 |
15 | 3ac0688a251 |
hex | 1f378bcaaef |
2145214311151 has 2 divisors, whose sum is σ = 2145214311152. Its totient is φ = 2145214311150.
The previous prime is 2145214311139. The next prime is 2145214311161. The reversal of 2145214311151 is 1511134125412.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2145214311151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2145214311161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1072607155575 + 1072607155576.
It is an arithmetic number, because the mean of its divisors is an integer number (1072607155576).
Almost surely, 22145214311151 is an apocalyptic number.
2145214311151 is a deficient number, since it is larger than the sum of its proper divisors (1).
2145214311151 is an equidigital number, since it uses as much as digits as its factorization.
2145214311151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4800, while the sum is 31.
Adding to 2145214311151 its reverse (1511134125412), we get a palindrome (3656348436563).
The spelling of 2145214311151 in words is "two trillion, one hundred forty-five billion, two hundred fourteen million, three hundred eleven thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •