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21453631468931 is a prime number
BaseRepresentation
bin1001110000011000100000…
…00101010011010110000011
32210221221120110112012121202
410320030100011103112003
510302444014124001211
6113343355013211415
74342654662443444
oct470142005232603
983857513465552
1021453631468931
11692148573a772
1224a5a35930b6b
13bc80b81081bc
1454250b5b92cb
152730d15b653b
hex138310153583

21453631468931 has 2 divisors, whose sum is σ = 21453631468932. Its totient is φ = 21453631468930.

The previous prime is 21453631468921. The next prime is 21453631468933. The reversal of 21453631468931 is 13986413635412.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21453631468931 - 222 = 21453627274627 is a prime.

It is a super-2 number, since 2×214536314689312 (a number of 27 digits) contains 22 as substring.

Together with 21453631468933, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (21453631468933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10726815734465 + 10726815734466.

It is an arithmetic number, because the mean of its divisors is an integer number (10726815734466).

Almost surely, 221453631468931 is an apocalyptic number.

21453631468931 is a deficient number, since it is larger than the sum of its proper divisors (1).

21453631468931 is an equidigital number, since it uses as much as digits as its factorization.

21453631468931 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11197440, while the sum is 56.

The spelling of 21453631468931 in words is "twenty-one trillion, four hundred fifty-three billion, six hundred thirty-one million, four hundred sixty-eight thousand, nine hundred thirty-one".