Base | Representation |
---|---|
bin | 11111001111011001010… |
… | …011010000110111101011 |
3 | 21121020100120122112100220 |
4 | 133033121103100313223 |
5 | 240133204100331121 |
6 | 4322124143301123 |
7 | 311050362124131 |
oct | 37173123206753 |
9 | 7536316575326 |
10 | 2146834386411 |
11 | 758516052660 |
12 | 2a80a25aa7a3 |
13 | 1275a40246a0 |
14 | 75c9ba47751 |
15 | 3ac9dc026c6 |
hex | 1f3d94d0deb |
2146834386411 has 32 divisors (see below), whose sum is σ = 3367247009280. Its totient is φ = 1199464243200.
The previous prime is 2146834386391. The next prime is 2146834386413. The reversal of 2146834386411 is 1146834386412.
It is not a de Polignac number, because 2146834386411 - 223 = 2146825997803 is a prime.
It is a super-2 number, since 2×21468343864112 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2146834386413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2923855 + ... + 3583656.
It is an arithmetic number, because the mean of its divisors is an integer number (105226469040).
Almost surely, 22146834386411 is an apocalyptic number.
2146834386411 is a deficient number, since it is larger than the sum of its proper divisors (1220412622869).
2146834386411 is a wasteful number, since it uses less digits than its factorization.
2146834386411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6508307.
The product of its digits is 2654208, while the sum is 51.
Subtracting from 2146834386411 its reverse (1146834386412), we obtain a palindrome (999999999999).
The spelling of 2146834386411 in words is "two trillion, one hundred forty-six billion, eight hundred thirty-four million, three hundred eighty-six thousand, four hundred eleven".
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