Base | Representation |
---|---|
bin | 11111001111011001010… |
… | …011010000110111101101 |
3 | 21121020100120122112100222 |
4 | 133033121103100313231 |
5 | 240133204100331123 |
6 | 4322124143301125 |
7 | 311050362124133 |
oct | 37173123206755 |
9 | 7536316575328 |
10 | 2146834386413 |
11 | 758516052662 |
12 | 2a80a25aa7a5 |
13 | 1275a40246a2 |
14 | 75c9ba47753 |
15 | 3ac9dc026c8 |
hex | 1f3d94d0ded |
2146834386413 has 2 divisors, whose sum is σ = 2146834386414. Its totient is φ = 2146834386412.
The previous prime is 2146834386391. The next prime is 2146834386419. The reversal of 2146834386413 is 3146834386412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1163837488969 + 982996897444 = 1078813^2 + 991462^2 .
It is a cyclic number.
It is not a de Polignac number, because 2146834386413 - 220 = 2146833337837 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2146834386419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1073417193206 + 1073417193207.
It is an arithmetic number, because the mean of its divisors is an integer number (1073417193207).
Almost surely, 22146834386413 is an apocalyptic number.
It is an amenable number.
2146834386413 is a deficient number, since it is larger than the sum of its proper divisors (1).
2146834386413 is an equidigital number, since it uses as much as digits as its factorization.
2146834386413 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7962624, while the sum is 53.
Subtracting 2146834386413 from its reverse (3146834386412), we obtain a palindrome (999999999999).
The spelling of 2146834386413 in words is "two trillion, one hundred forty-six billion, eight hundred thirty-four million, three hundred eighty-six thousand, four hundred thirteen".
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