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214710407 is a prime number
BaseRepresentation
bin11001100110000…
…11100010000111
3112222000102022022
430303003202013
5414431213112
633145553355
75215002602
oct1463034207
9488012268
10214710407
1110022011a
125baa585b
1335637ba2
1420731339
1513cb2d72
hexccc3887

214710407 has 2 divisors, whose sum is σ = 214710408. Its totient is φ = 214710406.

The previous prime is 214710343. The next prime is 214710427. The reversal of 214710407 is 704017412.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 214710407 - 26 = 214710343 is a prime.

It is a super-2 number, since 2×2147104072 = 92201117748211298, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (214710427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107355203 + 107355204.

It is an arithmetic number, because the mean of its divisors is an integer number (107355204).

Almost surely, 2214710407 is an apocalyptic number.

214710407 is a deficient number, since it is larger than the sum of its proper divisors (1).

214710407 is an equidigital number, since it uses as much as digits as its factorization.

214710407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1568, while the sum is 26.

The square root of 214710407 is about 14652.9999317546. Note that the first 4 decimals coincide. The cubic root of 214710407 is about 598.8035481649.

Adding to 214710407 its reverse (704017412), we get a palindrome (918727819).

The spelling of 214710407 in words is "two hundred fourteen million, seven hundred ten thousand, four hundred seven".