2147500622411 has 2 divisors, whose sum is σ = 2147500622412. Its totient is φ = 2147500622410.

The previous prime is 2147500622381. The next prime is 2147500622413. The reversal of 2147500622411 is 1142260057412.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2147500622411 is a prime.

It is a super-2 number, since 2×2147500622411² (a number of 25 digits) contains 22 as substring.

Together with 2147500622413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2147500622413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1073750311205 + 1073750311206.

It is an arithmetic number, because the mean of its divisors is an integer number (1073750311206).

Almost surely, 2^{2147500622411} is an apocalyptic number.

2147500622411 is a deficient number, since it is larger than the sum of its proper divisors (1).

2147500622411 is an equidigital number, since it uses as much as digits as its factorization.

2147500622411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26880, while the sum is 35.

Adding to 2147500622411 its reverse (1142260057412), we get a palindrome (3289760679823).

The spelling of 2147500622411 in words is "two trillion, one hundred forty-seven billion, five hundred million, six hundred twenty-two thousand, four hundred eleven".