Base | Representation |
---|---|
bin | 11111010001100001010… |
… | …000101001101111110011 |
3 | 21121110020112210012020002 |
4 | 133101201100221233303 |
5 | 240202342020401001 |
6 | 4323142345340215 |
7 | 311161040343035 |
oct | 37214120515763 |
9 | 7543215705202 |
10 | 2149115403251 |
11 | 759486688343 |
12 | 2a861a49766b |
13 | 1278787811ab |
14 | 76036973c55 |
15 | 3ad840c446b |
hex | 1f461429bf3 |
2149115403251 has 2 divisors, whose sum is σ = 2149115403252. Its totient is φ = 2149115403250.
The previous prime is 2149115403241. The next prime is 2149115403311. The reversal of 2149115403251 is 1523045119412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2149115403251 - 230 = 2148041661427 is a prime.
It is not a weakly prime, because it can be changed into another prime (2149115403241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1074557701625 + 1074557701626.
It is an arithmetic number, because the mean of its divisors is an integer number (1074557701626).
Almost surely, 22149115403251 is an apocalyptic number.
2149115403251 is a deficient number, since it is larger than the sum of its proper divisors (1).
2149115403251 is an equidigital number, since it uses as much as digits as its factorization.
2149115403251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 38.
The spelling of 2149115403251 in words is "two trillion, one hundred forty-nine billion, one hundred fifteen million, four hundred three thousand, two hundred fifty-one".
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