Base | Representation |
---|---|
bin | 11001101000010… |
… | …00101001001001 |
3 | 112222112210121112 |
4 | 30310020221021 |
5 | 420014242411 |
6 | 33200020105 |
7 | 5220262103 |
oct | 1464105111 |
9 | 488483545 |
10 | 214993481 |
11 | 1003a386a |
12 | 60001635 |
13 | 357069a1 |
14 | 207a6573 |
15 | 13d1bb8b |
hex | cd08a49 |
214993481 has 2 divisors, whose sum is σ = 214993482. Its totient is φ = 214993480.
The previous prime is 214993477. The next prime is 214993483. The reversal of 214993481 is 184399412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 206899456 + 8094025 = 14384^2 + 2845^2 .
It is a cyclic number.
It is not a de Polignac number, because 214993481 - 22 = 214993477 is a prime.
It is a super-2 number, since 2×2149934812 = 92444393744994722, which contains 22 as substring.
Together with 214993483, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (214993483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107496740 + 107496741.
It is an arithmetic number, because the mean of its divisors is an integer number (107496741).
Almost surely, 2214993481 is an apocalyptic number.
It is an amenable number.
214993481 is a deficient number, since it is larger than the sum of its proper divisors (1).
214993481 is an equidigital number, since it uses as much as digits as its factorization.
214993481 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 62208, while the sum is 41.
The square root of 214993481 is about 14662.6560008751. The cubic root of 214993481 is about 599.0665866151.
The spelling of 214993481 in words is "two hundred fourteen million, nine hundred ninety-three thousand, four hundred eighty-one".
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