Base | Representation |
---|---|
bin | 1001110001101111000110… |
… | …10010110000110111100111 |
3 | 2211010101120122200012020111 |
4 | 10320313203102300313213 |
5 | 10304224223403211041 |
6 | 113421004303513451 |
7 | 4346222063203132 |
oct | 470674322606747 |
9 | 84111518605214 |
10 | 21500124663271 |
11 | 693a173957821 |
12 | 24b2a502b8887 |
13 | bcc5b7497997 |
14 | 54487c299219 |
15 | 274403157981 |
hex | 138de34b0de7 |
21500124663271 has 2 divisors, whose sum is σ = 21500124663272. Its totient is φ = 21500124663270.
The previous prime is 21500124663263. The next prime is 21500124663307. The reversal of 21500124663271 is 17236642100512.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21500124663271 - 23 = 21500124663263 is a prime.
It is a super-3 number, since 3×215001246632713 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21500124663071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10750062331635 + 10750062331636.
It is an arithmetic number, because the mean of its divisors is an integer number (10750062331636).
Almost surely, 221500124663271 is an apocalyptic number.
21500124663271 is a deficient number, since it is larger than the sum of its proper divisors (1).
21500124663271 is an equidigital number, since it uses as much as digits as its factorization.
21500124663271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 40.
Adding to 21500124663271 its reverse (17236642100512), we get a palindrome (38736766763783).
The spelling of 21500124663271 in words is "twenty-one trillion, five hundred billion, one hundred twenty-four million, six hundred sixty-three thousand, two hundred seventy-one".
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