Base | Representation |
---|---|
bin | 11111010010011000111… |
… | …110010100110111110101 |
3 | 21121112122200121220000102 |
4 | 133102120332110313311 |
5 | 240211300312421003 |
6 | 4323415215523445 |
7 | 311223150336164 |
oct | 37223076246765 |
9 | 7545580556012 |
10 | 2150050123253 |
11 | 75991627430a |
12 | 2a883b529585 |
13 | 127997313056 |
14 | 760c4b6b3db |
15 | 3addb1ad588 |
hex | 1f498f94df5 |
2150050123253 has 2 divisors, whose sum is σ = 2150050123254. Its totient is φ = 2150050123252.
The previous prime is 2150050123213. The next prime is 2150050123357. The reversal of 2150050123253 is 3523210500512.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1315900354129 + 834149769124 = 1147127^2 + 913318^2 .
It is a cyclic number.
It is not a de Polignac number, because 2150050123253 - 26 = 2150050123189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2150050123213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075025061626 + 1075025061627.
It is an arithmetic number, because the mean of its divisors is an integer number (1075025061627).
Almost surely, 22150050123253 is an apocalyptic number.
It is an amenable number.
2150050123253 is a deficient number, since it is larger than the sum of its proper divisors (1).
2150050123253 is an equidigital number, since it uses as much as digits as its factorization.
2150050123253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9000, while the sum is 29.
Adding to 2150050123253 its reverse (3523210500512), we get a palindrome (5673260623765).
The spelling of 2150050123253 in words is "two trillion, one hundred fifty billion, fifty million, one hundred twenty-three thousand, two hundred fifty-three".
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