Base | Representation |
---|---|
bin | 11001101000100… |
… | …01100110000011 |
3 | 112222121122220112 |
4 | 30310101212003 |
5 | 420021431042 |
6 | 33200501535 |
7 | 5220504023 |
oct | 1464214603 |
9 | 488548815 |
10 | 215030147 |
11 | 100419372 |
12 | 6001a8ab |
13 | 3571a597 |
14 | 207b5a83 |
15 | 13d27982 |
hex | cd11983 |
215030147 has 2 divisors, whose sum is σ = 215030148. Its totient is φ = 215030146.
The previous prime is 215030129. The next prime is 215030149. The reversal of 215030147 is 741030512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 215030147 - 210 = 215029123 is a prime.
Together with 215030149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (215030149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107515073 + 107515074.
It is an arithmetic number, because the mean of its divisors is an integer number (107515074).
Almost surely, 2215030147 is an apocalyptic number.
215030147 is a deficient number, since it is larger than the sum of its proper divisors (1).
215030147 is an equidigital number, since it uses as much as digits as its factorization.
215030147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 23.
The square root of 215030147 is about 14663.9062667490. The cubic root of 215030147 is about 599.1006405575.
Adding to 215030147 its reverse (741030512), we get a palindrome (956060659).
The spelling of 215030147 in words is "two hundred fifteen million, thirty thousand, one hundred forty-seven".
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