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2150401002433 is a prime number
BaseRepresentation
bin11111010010101101111…
…000110100101111000001
321121120120010212101202121
4133102231320310233001
5240213010124034213
64323514112244241
7311234640634435
oct37225570645701
97546503771677
102150401002433
11759a8633a002
122a8918b40681
13127a21c16478
14761195c69c5
153ae0bdbc88d
hex1f4ade34bc1

2150401002433 has 2 divisors, whose sum is σ = 2150401002434. Its totient is φ = 2150401002432.

The previous prime is 2150401002397. The next prime is 2150401002437. The reversal of 2150401002433 is 3342001040512.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1194587792784 + 955813209649 = 1092972^2 + 977657^2 .

It is a cyclic number.

It is not a de Polignac number, because 2150401002433 - 237 = 2012962048961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2150401002398 and 2150401002407.

It is not a weakly prime, because it can be changed into another prime (2150401002437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075200501216 + 1075200501217.

It is an arithmetic number, because the mean of its divisors is an integer number (1075200501217).

Almost surely, 22150401002433 is an apocalyptic number.

It is an amenable number.

2150401002433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2150401002433 is an equidigital number, since it uses as much as digits as its factorization.

2150401002433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 2150401002433 its reverse (3342001040512), we get a palindrome (5492402042945).

The spelling of 2150401002433 in words is "two trillion, one hundred fifty billion, four hundred one million, two thousand, four hundred thirty-three".