Base | Representation |
---|---|
bin | 1001110001111010001011… |
… | …10110100010000101000111 |
3 | 2211010221221012211212101101 |
4 | 10320331011312202011013 |
5 | 10304323414213034333 |
6 | 113423430441040531 |
7 | 4346522353543042 |
oct | 470750566420507 |
9 | 84127835755341 |
10 | 21506073174343 |
11 | 694174671017a |
12 | 24b4030486147 |
13 | c000249a6714 |
14 | 544c84303c59 |
15 | 2746504be67d |
hex | 138f45da2147 |
21506073174343 has 2 divisors, whose sum is σ = 21506073174344. Its totient is φ = 21506073174342.
The previous prime is 21506073174293. The next prime is 21506073174403. The reversal of 21506073174343 is 34347137060512.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21506073174343 is a prime.
It is a super-2 number, since 2×215060731743432 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21506073174293 and 21506073174302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21506073144343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10753036587171 + 10753036587172.
It is an arithmetic number, because the mean of its divisors is an integer number (10753036587172).
Almost surely, 221506073174343 is an apocalyptic number.
21506073174343 is a deficient number, since it is larger than the sum of its proper divisors (1).
21506073174343 is an equidigital number, since it uses as much as digits as its factorization.
21506073174343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1270080, while the sum is 46.
The spelling of 21506073174343 in words is "twenty-one trillion, five hundred six billion, seventy-three million, one hundred seventy-four thousand, three hundred forty-three".
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