Base | Representation |
---|---|
bin | 11111010011010001110… |
… | …010000100111001100001 |
3 | 21121122010010000212220211 |
4 | 133103101302010321201 |
5 | 240220223310312114 |
6 | 4324053543534121 |
7 | 311255602432531 |
oct | 37232162047141 |
9 | 7548103025824 |
10 | 2151003213409 |
11 | 75a265268026 |
12 | 2a8a6675a341 |
13 | 127ab990751b |
14 | 761755874c1 |
15 | 3ae44bc56c4 |
hex | 1f4d1c84e61 |
2151003213409 has 2 divisors, whose sum is σ = 2151003213410. Its totient is φ = 2151003213408.
The previous prime is 2151003213377. The next prime is 2151003213467. The reversal of 2151003213409 is 9043123001512.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1107867817809 + 1043135395600 = 1052553^2 + 1021340^2 .
It is a cyclic number.
It is not a de Polignac number, because 2151003213409 - 25 = 2151003213377 is a prime.
It is not a weakly prime, because it can be changed into another prime (2151003213109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075501606704 + 1075501606705.
It is an arithmetic number, because the mean of its divisors is an integer number (1075501606705).
Almost surely, 22151003213409 is an apocalyptic number.
It is an amenable number.
2151003213409 is a deficient number, since it is larger than the sum of its proper divisors (1).
2151003213409 is an equidigital number, since it uses as much as digits as its factorization.
2151003213409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 31.
The spelling of 2151003213409 in words is "two trillion, one hundred fifty-one billion, three million, two hundred thirteen thousand, four hundred nine".
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