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2151012433 is a prime number
BaseRepresentation
bin1000000000110101…
…1101100001010001
312112220111202100011
42000031131201101
513401124344213
6553235354521
7104206206163
oct20015354121
95486452304
102151012433
11a04210529
12500452a41
1328383c02b
14165968933
15c8c9203d
hex8035d851

2151012433 has 2 divisors, whose sum is σ = 2151012434. Its totient is φ = 2151012432.

The previous prime is 2151012377. The next prime is 2151012443. The reversal of 2151012433 is 3342101512.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1706350864 + 444661569 = 41308^2 + 21087^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2151012433 is a prime.

It is not a weakly prime, because it can be changed into another prime (2151012443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075506216 + 1075506217.

It is an arithmetic number, because the mean of its divisors is an integer number (1075506217).

Almost surely, 22151012433 is an apocalyptic number.

It is an amenable number.

2151012433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2151012433 is an equidigital number, since it uses as much as digits as its factorization.

2151012433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 2151012433 is about 46379.0085383463. The cubic root of 2151012433 is about 1290.8654395324.

Adding to 2151012433 its reverse (3342101512), we get a palindrome (5493113945).

The spelling of 2151012433 in words is "two billion, one hundred fifty-one million, twelve thousand, four hundred thirty-three".