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21512311333 = 199250343189
BaseRepresentation
bin10100000010001110…
…111101001000100101
32001112020012122101121
4110002032331020211
5323024122430313
613514351253541
71361044425562
oct240216751045
961466178347
1021512311333
11913a1589a7
12420451a2b1
13204aaba806
1410810b1869
1585d8e828d
hex5023bd225

21512311333 has 8 divisors (see below), whose sum is σ = 21629552000. Its totient is φ = 21395162448.

The previous prime is 21512311321. The next prime is 21512311339. The reversal of 21512311333 is 33311321512.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21512311333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21512311298 and 21512311307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21512311339) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 476503 + ... + 519691.

It is an arithmetic number, because the mean of its divisors is an integer number (2703694000).

Almost surely, 221512311333 is an apocalyptic number.

It is an amenable number.

21512311333 is a deficient number, since it is larger than the sum of its proper divisors (117240667).

21512311333 is a wasteful number, since it uses less digits than its factorization.

21512311333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45891.

The product of its digits is 1620, while the sum is 25.

Adding to 21512311333 its reverse (33311321512), we get a palindrome (54823632845).

The spelling of 21512311333 in words is "twenty-one billion, five hundred twelve million, three hundred eleven thousand, three hundred thirty-three".

Divisors: 1 199 2503 43189 498097 8594611 108102067 21512311333