Base | Representation |
---|---|
bin | 11111010011100000000… |
… | …010100101010100000111 |
3 | 21121122201210010220202011 |
4 | 133103200002211110013 |
5 | 240221221024442021 |
6 | 4324133410555051 |
7 | 311264535606331 |
oct | 37234002452407 |
9 | 7548653126664 |
10 | 2151242421511 |
11 | 75a37829a677 |
12 | 2a8b12898a87 |
13 | 127b2733ba91 |
14 | 76199254451 |
15 | 3ae5abc6de1 |
hex | 1f4e00a5507 |
2151242421511 has 4 divisors (see below), whose sum is σ = 2151462642400. Its totient is φ = 2151022200624.
The previous prime is 2151242421421. The next prime is 2151242421547. The reversal of 2151242421511 is 1151242421512.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2151242421511 - 231 = 2149094937863 is a prime.
It is a super-2 number, since 2×21512424215112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2151242421551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110095791 + ... + 110115328.
It is an arithmetic number, because the mean of its divisors is an integer number (537865660600).
Almost surely, 22151242421511 is an apocalyptic number.
2151242421511 is a deficient number, since it is larger than the sum of its proper divisors (220220889).
2151242421511 is an equidigital number, since it uses as much as digits as its factorization.
2151242421511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 220220888.
The product of its digits is 6400, while the sum is 31.
Subtracting from 2151242421511 its reverse (1151242421512), we obtain a palindrome (999999999999).
The spelling of 2151242421511 in words is "two trillion, one hundred fifty-one billion, two hundred forty-two million, four hundred twenty-one thousand, five hundred eleven".
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