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21512501109553 is a prime number
BaseRepresentation
bin1001110010000110001001…
…11111001010001100110001
32211011120112012010210210211
410321003010333022030301
510304430100241001203
6113430412342024121
74350140555231656
oct471030477121461
984146465123724
1021512501109553
116944445057023
1224b5325118041
13c0080a614c8c
145452d3ca9c2d
152748c9987c6d
hex1390c4fca331

21512501109553 has 2 divisors, whose sum is σ = 21512501109554. Its totient is φ = 21512501109552.

The previous prime is 21512501109551. The next prime is 21512501109611. The reversal of 21512501109553 is 35590110521512.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19346520747024 + 2165980362529 = 4398468^2 + 1471727^2 .

It is a cyclic number.

It is not a de Polignac number, because 21512501109553 - 21 = 21512501109551 is a prime.

It is a super-2 number, since 2×215125011095532 (a number of 27 digits) contains 22 as substring.

Together with 21512501109551, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (21512501109551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10756250554776 + 10756250554777.

It is an arithmetic number, because the mean of its divisors is an integer number (10756250554777).

Almost surely, 221512501109553 is an apocalyptic number.

It is an amenable number.

21512501109553 is a deficient number, since it is larger than the sum of its proper divisors (1).

21512501109553 is an equidigital number, since it uses as much as digits as its factorization.

21512501109553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 67500, while the sum is 40.

The spelling of 21512501109553 in words is "twenty-one trillion, five hundred twelve billion, five hundred one million, one hundred nine thousand, five hundred fifty-three".