2151254054407 has 2 divisors, whose sum is σ = 2151254054408. Its totient is φ = 2151254054406.

The previous prime is 2151254054309. The next prime is 2151254054429. The reversal of 2151254054407 is 7044504521512.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2151254054407 - 2¹⁵ = 2151254021639 is a prime.

It is a super-2 number, since 2×2151254054407² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2151254054407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2151254054437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1075627027203 + 1075627027204.

It is an arithmetic number, because the mean of its divisors is an integer number (1075627027204).

Almost surely, 2^{2151254054407} is an apocalyptic number.

2151254054407 is a deficient number, since it is larger than the sum of its proper divisors (1).

2151254054407 is an equidigital number, since it uses as much as digits as its factorization.

2151254054407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 224000, while the sum is 40.

Adding to 2151254054407 its reverse (7044504521512), we get a palindrome (9195758575919).

The spelling of 2151254054407 in words is "two trillion, one hundred fifty-one billion, two hundred fifty-four million, fifty-four thousand, four hundred seven".