Base | Representation |
---|---|
bin | 1100100001011011000… |
… | …0101101110101000101 |
3 | 202120021210111012220011 |
4 | 3020112300231311011 |
5 | 12011041314443211 |
6 | 242455055310221 |
7 | 21354061550632 |
oct | 3102660556505 |
9 | 676253435804 |
10 | 215130234181 |
11 | 83266455075 |
12 | 3583a81b371 |
13 | 17395b36475 |
14 | a5ab727189 |
15 | 58e1911921 |
hex | 3216c2dd45 |
215130234181 has 2 divisors, whose sum is σ = 215130234182. Its totient is φ = 215130234180.
The previous prime is 215130234091. The next prime is 215130234251. The reversal of 215130234181 is 181432031512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 210910562500 + 4219671681 = 459250^2 + 64959^2 .
It is a cyclic number.
It is not a de Polignac number, because 215130234181 - 211 = 215130232133 is a prime.
It is a super-2 number, since 2×2151302341812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (215130231181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107565117090 + 107565117091.
It is an arithmetic number, because the mean of its divisors is an integer number (107565117091).
Almost surely, 2215130234181 is an apocalyptic number.
It is an amenable number.
215130234181 is a deficient number, since it is larger than the sum of its proper divisors (1).
215130234181 is an equidigital number, since it uses as much as digits as its factorization.
215130234181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 215130234181 its reverse (181432031512), we get a palindrome (396562265693).
The spelling of 215130234181 in words is "two hundred fifteen billion, one hundred thirty million, two hundred thirty-four thousand, one hundred eighty-one".
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