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21515453424133 is a prime number
BaseRepresentation
bin1001110010001011101001…
…11101010110001000000101
32211011212010221102221001021
410321011310331112020011
510310002122034033013
6113432021324231141
74350303664420054
oct471056475261005
984155127387037
1021515453424133
11694571a607729
1224b5a0999b4b1
13c00b8b171796
145454d401c39b
152749edc5ca8d
hex139174f56205

21515453424133 has 2 divisors, whose sum is σ = 21515453424134. Its totient is φ = 21515453424132.

The previous prime is 21515453424011. The next prime is 21515453424187. The reversal of 21515453424133 is 33142435451512.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15326269754884 + 6189183669249 = 3914878^2 + 2487807^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21515453424133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21515453424133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21515453424233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10757726712066 + 10757726712067.

It is an arithmetic number, because the mean of its divisors is an integer number (10757726712067).

Almost surely, 221515453424133 is an apocalyptic number.

It is an amenable number.

21515453424133 is a deficient number, since it is larger than the sum of its proper divisors (1).

21515453424133 is an equidigital number, since it uses as much as digits as its factorization.

21515453424133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 864000, while the sum is 43.

Adding to 21515453424133 its reverse (33142435451512), we get a palindrome (54657888875645).

The spelling of 21515453424133 in words is "twenty-one trillion, five hundred fifteen billion, four hundred fifty-three million, four hundred twenty-four thousand, one hundred thirty-three".