Base | Representation |
---|---|
bin | 11111010100001101011… |
… | …001100000010011001011 |
3 | 21121201200211001212211221 |
4 | 133110031121200103023 |
5 | 240224300332430003 |
6 | 4324341113302511 |
7 | 311322436062154 |
oct | 37241531402313 |
9 | 7551624055757 |
10 | 2152003405003 |
11 | 75a728901851 |
12 | 2a90a5704a37 |
13 | 127c18bb097a |
14 | 7622c34492b |
15 | 3aea28e37bd |
hex | 1f50d6604cb |
2152003405003 has 2 divisors, whose sum is σ = 2152003405004. Its totient is φ = 2152003405002.
The previous prime is 2152003404931. The next prime is 2152003405037. The reversal of 2152003405003 is 3005043002512.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2152003405003 is a prime.
It is a super-2 number, since 2×21520034050032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2152003705003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076001702501 + 1076001702502.
It is an arithmetic number, because the mean of its divisors is an integer number (1076001702502).
Almost surely, 22152003405003 is an apocalyptic number.
2152003405003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2152003405003 is an equidigital number, since it uses as much as digits as its factorization.
2152003405003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 25.
Adding to 2152003405003 its reverse (3005043002512), we get a palindrome (5157046407515).
The spelling of 2152003405003 in words is "two trillion, one hundred fifty-two billion, three million, four hundred five thousand, three".
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