Base | Representation |
---|---|
bin | 11111010100100101110… |
… | …100100100001111001111 |
3 | 21121202202101002012100022 |
4 | 133110211310210033033 |
5 | 240231120231332312 |
6 | 4324445511452355 |
7 | 311335542631343 |
oct | 37244564441717 |
9 | 7552671065308 |
10 | 2152413152207 |
11 | 75a9191249aa |
12 | 2a919a9870bb |
13 | 127c82a55a36 |
14 | 7626a925623 |
15 | 3aec8880172 |
hex | 1f525d243cf |
2152413152207 has 2 divisors, whose sum is σ = 2152413152208. Its totient is φ = 2152413152206.
The previous prime is 2152413152159. The next prime is 2152413152233. The reversal of 2152413152207 is 7022513142512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2152413152207 - 212 = 2152413148111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2152413142207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076206576103 + 1076206576104.
It is an arithmetic number, because the mean of its divisors is an integer number (1076206576104).
Almost surely, 22152413152207 is an apocalyptic number.
2152413152207 is a deficient number, since it is larger than the sum of its proper divisors (1).
2152413152207 is an equidigital number, since it uses as much as digits as its factorization.
2152413152207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 33600, while the sum is 35.
Adding to 2152413152207 its reverse (7022513142512), we get a palindrome (9174926294719).
The spelling of 2152413152207 in words is "two trillion, one hundred fifty-two billion, four hundred thirteen million, one hundred fifty-two thousand, two hundred seven".
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