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21525114031 = 53406134227
BaseRepresentation
bin10100000010111111…
…110010110010101111
32001120010022002101121
4110002333302302233
5323040412122111
613515525521411
71361261310331
oct240277626257
961503262347
1021525114031
119146402843
124208873267
132050650c85
141082a85451
1585eac6871
hex502ff2caf

21525114031 has 4 divisors (see below), whose sum is σ = 21931248312. Its totient is φ = 21118979752.

The previous prime is 21525114011. The next prime is 21525114067. The reversal of 21525114031 is 13041152512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21525114031 is a prime.

It is a super-2 number, since 2×215251140312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21525113987 and 21525114005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21525114011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203067061 + ... + 203067166.

It is an arithmetic number, because the mean of its divisors is an integer number (5482812078).

Almost surely, 221525114031 is an apocalyptic number.

21525114031 is a deficient number, since it is larger than the sum of its proper divisors (406134281).

21525114031 is an equidigital number, since it uses as much as digits as its factorization.

21525114031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 406134280.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 21525114031 its reverse (13041152512), we get a palindrome (34566266543).

The spelling of 21525114031 in words is "twenty-one billion, five hundred twenty-five million, one hundred fourteen thousand, thirty-one".

Divisors: 1 53 406134227 21525114031