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215251425300001 is a prime number
BaseRepresentation
bin110000111100010100100000…
…101111100000111000100001
31001020010211112221001000222011
4300330110200233200320201
5211203134404334100001
62041445050055512521
763224254660351516
oct6074244057407041
91036124487030864
10215251425300001
1162649686a97062
1220185202988741
13931517893690c
143b2232032730d
1519d42b470dd51
hexc3c520be0e21

215251425300001 has 2 divisors, whose sum is σ = 215251425300002. Its totient is φ = 215251425300000.

The previous prime is 215251425299983. The next prime is 215251425300013. The reversal of 215251425300001 is 100003524152512.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 212378129093601 + 2873296206400 = 14573199^2 + 1695080^2 .

It is a cyclic number.

It is not a de Polignac number, because 215251425300001 - 225 = 215251391745569 is a prime.

It is not a weakly prime, because it can be changed into another prime (215251425300601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107625712650000 + 107625712650001.

It is an arithmetic number, because the mean of its divisors is an integer number (107625712650001).

Almost surely, 2215251425300001 is an apocalyptic number.

It is an amenable number.

215251425300001 is a deficient number, since it is larger than the sum of its proper divisors (1).

215251425300001 is an equidigital number, since it uses as much as digits as its factorization.

215251425300001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 215251425300001 its reverse (100003524152512), we get a palindrome (315254949452513).

The spelling of 215251425300001 in words is "two hundred fifteen trillion, two hundred fifty-one billion, four hundred twenty-five million, three hundred thousand, one".