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215251425300013 is a prime number
BaseRepresentation
bin110000111100010100100000…
…101111100000111000101101
31001020010211112221001000222121
4300330110200233200320231
5211203134404334100023
62041445050055512541
763224254660351534
oct6074244057407055
91036124487030877
10215251425300013
1162649686a97073
1220185202988751
13931517893691b
143b2232032731b
1519d42b470dd5d
hexc3c520be0e2d

215251425300013 has 2 divisors, whose sum is σ = 215251425300014. Its totient is φ = 215251425300012.

The previous prime is 215251425300001. The next prime is 215251425300019. The reversal of 215251425300013 is 310003524152512.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 159244132924809 + 56007292375204 = 12619197^2 + 7483802^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-215251425300013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (215251425300019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107625712650006 + 107625712650007.

It is an arithmetic number, because the mean of its divisors is an integer number (107625712650007).

Almost surely, 2215251425300013 is an apocalyptic number.

It is an amenable number.

215251425300013 is a deficient number, since it is larger than the sum of its proper divisors (1).

215251425300013 is an equidigital number, since it uses as much as digits as its factorization.

215251425300013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36000, while the sum is 34.

Adding to 215251425300013 its reverse (310003524152512), we get a palindrome (525254949452525).

The spelling of 215251425300013 in words is "two hundred fifteen trillion, two hundred fifty-one billion, four hundred twenty-five million, three hundred thousand, thirteen".