Base | Representation |
---|---|
bin | 1001110010101001011001… |
… | …11001111010101111001111 |
3 | 2211020101100222201100102212 |
4 | 10321110230321322233033 |
5 | 10310232324123411101 |
6 | 113443222210341035 |
7 | 4351410524652311 |
oct | 471245471725717 |
9 | 84211328640385 |
10 | 21531424435151 |
11 | 6951475852694 |
12 | 24b8b2658a77b |
13 | c02534c17c67 |
14 | 5461ab1a57b1 |
15 | 275135e291bb |
hex | 13952ce7abcf |
21531424435151 has 2 divisors, whose sum is σ = 21531424435152. Its totient is φ = 21531424435150.
The previous prime is 21531424435141. The next prime is 21531424435273. The reversal of 21531424435151 is 15153442413512.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21531424435151 - 214 = 21531424418767 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 21531424435099 and 21531424435108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21531424435141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10765712217575 + 10765712217576.
It is an arithmetic number, because the mean of its divisors is an integer number (10765712217576).
Almost surely, 221531424435151 is an apocalyptic number.
21531424435151 is a deficient number, since it is larger than the sum of its proper divisors (1).
21531424435151 is an equidigital number, since it uses as much as digits as its factorization.
21531424435151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 288000, while the sum is 41.
Adding to 21531424435151 its reverse (15153442413512), we get a palindrome (36684866848663).
The spelling of 21531424435151 in words is "twenty-one trillion, five hundred thirty-one billion, four hundred twenty-four million, four hundred thirty-five thousand, one hundred fifty-one".
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