Base | Representation |
---|---|
bin | 11111010101010010000… |
… | …000001111101000000101 |
3 | 21121211200000220001021011 |
4 | 133111102000033220011 |
5 | 240234130012123023 |
6 | 4325051231322221 |
7 | 311363113342624 |
oct | 37252200175005 |
9 | 7554600801234 |
10 | 2153154411013 |
11 | 760169594691 |
12 | 2a9367080371 |
13 | 1280704ac908 |
14 | 762db15d6bb |
15 | 3b01d9a250d |
hex | 1f55200fa05 |
2153154411013 has 8 divisors (see below), whose sum is σ = 2199036728448. Its totient is φ = 2107275032064.
The previous prime is 2153154410989. The next prime is 2153154411017. The reversal of 2153154411013 is 3101144513512.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2153154411013 - 221 = 2153152313861 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2153154411017) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 779370 + ... + 2216692.
It is an arithmetic number, because the mean of its divisors is an integer number (274879591056).
Almost surely, 22153154411013 is an apocalyptic number.
It is an amenable number.
2153154411013 is a deficient number, since it is larger than the sum of its proper divisors (45882317435).
2153154411013 is a wasteful number, since it uses less digits than its factorization.
2153154411013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1469243.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 2153154411013 its reverse (3101144513512), we get a palindrome (5254298924525).
The spelling of 2153154411013 in words is "two trillion, one hundred fifty-three billion, one hundred fifty-four million, four hundred eleven thousand, thirteen".
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