Base | Representation |
---|---|
bin | 11111010101010010000… |
… | …010100010111010111011 |
3 | 21121211200002000200212021 |
4 | 133111102002202322323 |
5 | 240234130140424311 |
6 | 4325051252255311 |
7 | 311363121434566 |
oct | 37252202427273 |
9 | 7554602020767 |
10 | 2153155014331 |
11 | 7601699669a2 |
12 | 2a9367311537 |
13 | 1280706613c9 |
14 | 762db2794dd |
15 | 3b01da71171 |
hex | 1f5520a2ebb |
2153155014331 has 2 divisors, whose sum is σ = 2153155014332. Its totient is φ = 2153155014330.
The previous prime is 2153155014301. The next prime is 2153155014341. The reversal of 2153155014331 is 1334105513512.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2153155014331 is a prime.
It is a super-2 number, since 2×21531550143312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2153155014301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076577507165 + 1076577507166.
It is an arithmetic number, because the mean of its divisors is an integer number (1076577507166).
Almost surely, 22153155014331 is an apocalyptic number.
2153155014331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2153155014331 is an equidigital number, since it uses as much as digits as its factorization.
2153155014331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27000, while the sum is 34.
The spelling of 2153155014331 in words is "two trillion, one hundred fifty-three billion, one hundred fifty-five million, fourteen thousand, three hundred thirty-one".
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