Base | Representation |
---|---|
bin | 11111010101101111100… |
… | …100000000001010111101 |
3 | 21121212221121001001012122 |
4 | 133111233210000022331 |
5 | 240241133440333112 |
6 | 4325212344412325 |
7 | 311411314465553 |
oct | 37255744001275 |
9 | 7555847031178 |
10 | 2153650324157 |
11 | 7603a350a562 |
12 | 2a94851770a5 |
13 | 12811c163747 |
14 | 76346d6dbd3 |
15 | 3b04c2ae872 |
hex | 1f56f9002bd |
2153650324157 has 2 divisors, whose sum is σ = 2153650324158. Its totient is φ = 2153650324156.
The previous prime is 2153650324141. The next prime is 2153650324187. The reversal of 2153650324157 is 7514230563512.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1395672880996 + 757977443161 = 1181386^2 + 870619^2 .
It is a cyclic number.
It is not a de Polignac number, because 2153650324157 - 24 = 2153650324141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2153650324127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076825162078 + 1076825162079.
It is an arithmetic number, because the mean of its divisors is an integer number (1076825162079).
Almost surely, 22153650324157 is an apocalyptic number.
It is an amenable number.
2153650324157 is a deficient number, since it is larger than the sum of its proper divisors (1).
2153650324157 is an equidigital number, since it uses as much as digits as its factorization.
2153650324157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 756000, while the sum is 44.
Adding to 2153650324157 its reverse (7514230563512), we get a palindrome (9667880887669).
The spelling of 2153650324157 in words is "two trillion, one hundred fifty-three billion, six hundred fifty million, three hundred twenty-four thousand, one hundred fifty-seven".
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