Search a number
-
+
2154333512453 is a prime number
BaseRepresentation
bin11111010110011000010…
…010001010001100000101
321121221201012120121100212
4133112120102022030011
5240244033334344303
64325404231445205
7311434251500303
oct37263022121405
97557635517325
102154333512453
11760714116a91
122a9635b26805
131281ca867985
14763ad9ad273
153b08c260ad8
hex1f59848a305

2154333512453 has 2 divisors, whose sum is σ = 2154333512454. Its totient is φ = 2154333512452.

The previous prime is 2154333512339. The next prime is 2154333512483. The reversal of 2154333512453 is 3542153334512.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1948723865089 + 205609647364 = 1395967^2 + 453442^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2154333512453 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2154333512453.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2154333512483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077166756226 + 1077166756227.

It is an arithmetic number, because the mean of its divisors is an integer number (1077166756227).

Almost surely, 22154333512453 is an apocalyptic number.

It is an amenable number.

2154333512453 is a deficient number, since it is larger than the sum of its proper divisors (1).

2154333512453 is an equidigital number, since it uses as much as digits as its factorization.

2154333512453 is an evil number, because the sum of its binary digits is even.

The product of its digits is 648000, while the sum is 41.

Adding to 2154333512453 its reverse (3542153334512), we get a palindrome (5696486846965).

The spelling of 2154333512453 in words is "two trillion, one hundred fifty-four billion, three hundred thirty-three million, five hundred twelve thousand, four hundred fifty-three".