Base | Representation |
---|---|
bin | 1100100010100100100… |
… | …1011001011011111111 |
3 | 202121002021220121102012 |
4 | 3020221021121123333 |
5 | 12012204301203033 |
6 | 242545434521435 |
7 | 21364525454051 |
oct | 3105111313377 |
9 | 677067817365 |
10 | 215438694143 |
11 | 83404587662 |
12 | 35905b9627b |
13 | 17414a06b5a |
14 | a5da69d8d1 |
15 | 590da42248 |
hex | 32292596ff |
215438694143 has 2 divisors, whose sum is σ = 215438694144. Its totient is φ = 215438694142.
The previous prime is 215438694109. The next prime is 215438694167. The reversal of 215438694143 is 341496834512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 215438694143 - 216 = 215438628607 is a prime.
It is a super-2 number, since 2×2154386941432 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 215438694091 and 215438694100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (215438694173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107719347071 + 107719347072.
It is an arithmetic number, because the mean of its divisors is an integer number (107719347072).
Almost surely, 2215438694143 is an apocalyptic number.
215438694143 is a deficient number, since it is larger than the sum of its proper divisors (1).
215438694143 is an equidigital number, since it uses as much as digits as its factorization.
215438694143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2488320, while the sum is 50.
The spelling of 215438694143 in words is "two hundred fifteen billion, four hundred thirty-eight million, six hundred ninety-four thousand, one hundred forty-three".
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