Base | Representation |
---|---|
bin | 11111010111001000010… |
… | …111111011001011010101 |
3 | 21122000210102202012020112 |
4 | 133113020113323023111 |
5 | 240302211411031242 |
6 | 4330020252412405 |
7 | 311463246360521 |
oct | 37271027731325 |
9 | 7560712665215 |
10 | 2155140330197 |
11 | 760a98594108 |
12 | 2a9820177105 |
13 | 1282c8a66b1a |
14 | 76448bd0d81 |
15 | 3b0d7ed2c82 |
hex | 1f5c85fb2d5 |
2155140330197 has 2 divisors, whose sum is σ = 2155140330198. Its totient is φ = 2155140330196.
The previous prime is 2155140330181. The next prime is 2155140330257. The reversal of 2155140330197 is 7910330415512.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2048545263076 + 106595067121 = 1431274^2 + 326489^2 .
It is a cyclic number.
It is not a de Polignac number, because 2155140330197 - 24 = 2155140330181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2155140330107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077570165098 + 1077570165099.
It is an arithmetic number, because the mean of its divisors is an integer number (1077570165099).
Almost surely, 22155140330197 is an apocalyptic number.
It is an amenable number.
2155140330197 is a deficient number, since it is larger than the sum of its proper divisors (1).
2155140330197 is an equidigital number, since it uses as much as digits as its factorization.
2155140330197 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 113400, while the sum is 41.
The spelling of 2155140330197 in words is "two trillion, one hundred fifty-five billion, one hundred forty million, three hundred thirty thousand, one hundred ninety-seven".
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