Base | Representation |
---|---|
bin | 1001110011010000101011… |
… | …10010111000011101101101 |
3 | 2211022101210120211211202012 |
4 | 10321220111302320131231 |
5 | 10311104020424120331 |
6 | 113501030452411005 |
7 | 4353055220332211 |
oct | 471502562703555 |
9 | 84271716754665 |
10 | 21552511551341 |
11 | 695a406997141 |
12 | 2501030616a65 |
13 | c045158b21c4 |
14 | 54720b9d4941 |
15 | 27596c33382b |
hex | 139a15cb876d |
21552511551341 has 2 divisors, whose sum is σ = 21552511551342. Its totient is φ = 21552511551340.
The previous prime is 21552511551287. The next prime is 21552511551353. The reversal of 21552511551341 is 14315511525512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17490085873225 + 4062425678116 = 4182115^2 + 2015546^2 .
It is a cyclic number.
It is not a de Polignac number, because 21552511551341 - 234 = 21535331682157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21557511551341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10776255775670 + 10776255775671.
It is an arithmetic number, because the mean of its divisors is an integer number (10776255775671).
Almost surely, 221552511551341 is an apocalyptic number.
It is an amenable number.
21552511551341 is a deficient number, since it is larger than the sum of its proper divisors (1).
21552511551341 is an equidigital number, since it uses as much as digits as its factorization.
21552511551341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 150000, while the sum is 41.
The spelling of 21552511551341 in words is "twenty-one trillion, five hundred fifty-two billion, five hundred eleven million, five hundred fifty-one thousand, three hundred forty-one".
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