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215534132255531 is a prime number
BaseRepresentation
bin110001000000011011110011…
…011000111101101100101011
31001021010212021021001101100202
4301000123303120331230223
5211222302400324134111
62042223002523022415
763253553503002665
oct6100336330755453
91037125237041322
10215534132255531
116274856a771071
122020bb6096aa0b
139335a20b3b21b
143b31c9c8a7535
1519db80db0cb3b
hexc406f363db2b

215534132255531 has 2 divisors, whose sum is σ = 215534132255532. Its totient is φ = 215534132255530.

The previous prime is 215534132255513. The next prime is 215534132255539. The reversal of 215534132255531 is 135552231435512.

Together with previous prime (215534132255513) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 215534132255531 - 242 = 211136085744427 is a prime.

It is a super-2 number, since 2×2155341322555312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (215534132255539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107767066127765 + 107767066127766.

It is an arithmetic number, because the mean of its divisors is an integer number (107767066127766).

Almost surely, 2215534132255531 is an apocalyptic number.

215534132255531 is a deficient number, since it is larger than the sum of its proper divisors (1).

215534132255531 is an equidigital number, since it uses as much as digits as its factorization.

215534132255531 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2700000, while the sum is 47.

The spelling of 215534132255531 in words is "two hundred fifteen trillion, five hundred thirty-four billion, one hundred thirty-two million, two hundred fifty-five thousand, five hundred thirty-one".