Base | Representation |
---|---|
bin | 11111010111011110000… |
… | …011010000110001000101 |
3 | 21122001201210002011101011 |
4 | 133113132003100301011 |
5 | 240303433011343412 |
6 | 4330120323402221 |
7 | 311505253541413 |
oct | 37273603206105 |
9 | 7561653064334 |
10 | 2155504012357 |
11 | 761164903983 |
12 | 2a9901b23371 |
13 | 128356200877 |
14 | 764812202b3 |
15 | 3b109dc07a7 |
hex | 1f5de0d0c45 |
2155504012357 has 2 divisors, whose sum is σ = 2155504012358. Its totient is φ = 2155504012356.
The previous prime is 2155504012301. The next prime is 2155504012367. The reversal of 2155504012357 is 7532104055512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2148176823556 + 7327188801 = 1465666^2 + 85599^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2155504012357 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2155504012367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077752006178 + 1077752006179.
It is an arithmetic number, because the mean of its divisors is an integer number (1077752006179).
Almost surely, 22155504012357 is an apocalyptic number.
It is an amenable number.
2155504012357 is a deficient number, since it is larger than the sum of its proper divisors (1).
2155504012357 is an equidigital number, since it uses as much as digits as its factorization.
2155504012357 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 210000, while the sum is 40.
Adding to 2155504012357 its reverse (7532104055512), we get a palindrome (9687608067869).
The spelling of 2155504012357 in words is "two trillion, one hundred fifty-five billion, five hundred four million, twelve thousand, three hundred fifty-seven".
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