Base | Representation |
---|---|
bin | 11111011000000011100… |
… | …011000011110111111101 |
3 | 21122010100121211101110012 |
4 | 133120003203003313331 |
5 | 240311230033331044 |
6 | 4330302555153005 |
7 | 311526663000242 |
oct | 37300343036775 |
9 | 7563317741405 |
10 | 2156133105149 |
11 | 761457a22681 |
12 | 2a9a58745765 |
13 | 12842664451a |
14 | 765009bb5c9 |
15 | 3b14523859e |
hex | 1f6038c3dfd |
2156133105149 has 2 divisors, whose sum is σ = 2156133105150. Its totient is φ = 2156133105148.
The previous prime is 2156133105101. The next prime is 2156133105157. The reversal of 2156133105149 is 9415013316512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1636818301924 + 519314803225 = 1279382^2 + 720635^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2156133105149 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2156133105449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1078066552574 + 1078066552575.
It is an arithmetic number, because the mean of its divisors is an integer number (1078066552575).
Almost surely, 22156133105149 is an apocalyptic number.
It is an amenable number.
2156133105149 is a deficient number, since it is larger than the sum of its proper divisors (1).
2156133105149 is an equidigital number, since it uses as much as digits as its factorization.
2156133105149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 41.
The spelling of 2156133105149 in words is "two trillion, one hundred fifty-six billion, one hundred thirty-three million, one hundred five thousand, one hundred forty-nine".
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