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2157738066433 is a prime number
BaseRepresentation
bin11111011001100011001…
…101100000001000000001
321122021111110211212102201
4133121203031200020001
5240323021421111213
64331130131113201
7311614521642535
oct37314315401001
97567443755381
102157738066433
11762100982864
122aa226142801
13128620cc6561
1476613c03bc5
153b1db0b76dd
hex1f663360201

2157738066433 has 2 divisors, whose sum is σ = 2157738066434. Its totient is φ = 2157738066432.

The previous prime is 2157738066431. The next prime is 2157738066437. The reversal of 2157738066433 is 3346608377512.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1188649423504 + 969088642929 = 1090252^2 + 984423^2 .

It is a cyclic number.

It is not a de Polignac number, because 2157738066433 - 21 = 2157738066431 is a prime.

Together with 2157738066431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (2157738066431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1078869033216 + 1078869033217.

It is an arithmetic number, because the mean of its divisors is an integer number (1078869033217).

Almost surely, 22157738066433 is an apocalyptic number.

It is an amenable number.

2157738066433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2157738066433 is an equidigital number, since it uses as much as digits as its factorization.

2157738066433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15240960, while the sum is 55.

The spelling of 2157738066433 in words is "two trillion, one hundred fifty-seven billion, seven hundred thirty-eight million, sixty-six thousand, four hundred thirty-three".