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216188806048153 is a prime number
BaseRepresentation
bin110001001001111101100000…
…111111010010100110011001
31001100110110002121021212122021
4301021331200333102212121
5211314014133322020103
62043443433314254441
763352061102300221
oct6111754077224631
91040413077255567
10216188806048153
1162980180a90244
12202b6a09887421
1393826949215c3
143b558460a7081
1519ed8787dcbbd
hexc49f60fd2999

216188806048153 has 2 divisors, whose sum is σ = 216188806048154. Its totient is φ = 216188806048152.

The previous prime is 216188806048147. The next prime is 216188806048157. The reversal of 216188806048153 is 351840608881612.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 150147698589529 + 66041107458624 = 12253477^2 + 8126568^2 .

It is a cyclic number.

It is not a de Polignac number, because 216188806048153 - 213 = 216188806039961 is a prime.

It is a super-2 number, since 2×2161888060481532 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 216188806048091 and 216188806048100.

It is not a weakly prime, because it can be changed into another prime (216188806048157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 108094403024076 + 108094403024077.

It is an arithmetic number, because the mean of its divisors is an integer number (108094403024077).

Almost surely, 2216188806048153 is an apocalyptic number.

It is an amenable number.

216188806048153 is a deficient number, since it is larger than the sum of its proper divisors (1).

216188806048153 is an equidigital number, since it uses as much as digits as its factorization.

216188806048153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17694720, while the sum is 61.

The spelling of 216188806048153 in words is "two hundred sixteen trillion, one hundred eighty-eight billion, eight hundred six million, forty-eight thousand, one hundred fifty-three".